2x^2+7x+41=0

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Solution for 2x^2+7x+41=0 equation:


Simplifying
2x2 + 7x + 41 = 0

Reorder the terms:
41 + 7x + 2x2 = 0

Solving
41 + 7x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
20.5 + 3.5x + x2 = 0

Move the constant term to the right:

Add '-20.5' to each side of the equation.
20.5 + 3.5x + -20.5 + x2 = 0 + -20.5

Reorder the terms:
20.5 + -20.5 + 3.5x + x2 = 0 + -20.5

Combine like terms: 20.5 + -20.5 = 0.0
0.0 + 3.5x + x2 = 0 + -20.5
3.5x + x2 = 0 + -20.5

Combine like terms: 0 + -20.5 = -20.5
3.5x + x2 = -20.5

The x term is 3.5x.  Take half its coefficient (1.75).
Square it (3.0625) and add it to both sides.

Add '3.0625' to each side of the equation.
3.5x + 3.0625 + x2 = -20.5 + 3.0625

Reorder the terms:
3.0625 + 3.5x + x2 = -20.5 + 3.0625

Combine like terms: -20.5 + 3.0625 = -17.4375
3.0625 + 3.5x + x2 = -17.4375

Factor a perfect square on the left side:
(x + 1.75)(x + 1.75) = -17.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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